Input:
pdsolve(ds(y,t,1.5)=ds(y,x,1.5)-2y^2-4x*y-2x^2)
Write:
pdsolve(ds(y,t,1.5)=ds(y,x,1.5)-2y2-4x⋅y-2x2)
Compute:
pdsolve(d1.5ydt1.5=d1.5ydx1.5−2 y2−4 x y−2 x2)
Output:
pdsolve(d1.5ydt1.5=d1.5ydx1.5−2 y2−4 x y−2 x2)==−x+(−1.1283791670955126i) 1(2 C1+C2 exp(t+x)+x+C3 t x+C3 (0.7522527780636751 t1.5+0.7522527780636751 x1.5))1.5
Result: −x+(−1.1283791670955126i) 1(2 C1+C2 exp(t+x)+x+C3 t x+C3 (0.7522527780636751 t1.5+0.7522527780636751 x1.5))1.5
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