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Catenary Evolute

\begin{figure}\begin{center}\BoxedEPSF{CatenaryEvolute.epsf scaled 800}\end{center}\end{figure}


$\displaystyle x$ $\textstyle =$ $\displaystyle a[x-{\textstyle{1\over 2}}\sinh(2t)]$  
$\displaystyle y$ $\textstyle =$ $\displaystyle 2a\cosh t.$  




© 1996-9 Eric W. Weisstein
1999-05-26