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Composition Theorem

Let

\begin{displaymath}
Q(x,y)\equiv x^2+y^2.
\end{displaymath}

Then

\begin{displaymath}
Q(x,y)Q(x',y') = Q(xx'-yy',x'y+xy'),
\end{displaymath}

since

\begin{eqnarray*}
(x^2+y^2)(x'^2+y'^2)&=&(xx'-yy')^2+(xy'+x'y)^2\\
&=&x^2x'^2+y^2y'^2+x'^2y^2+x^2y'^2.
\end{eqnarray*}



See also Genus Theorem




© 1996-9 Eric W. Weisstein
1999-05-26