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Jordan's Inequality

\begin{figure}\begin{center}\BoxedEPSF{JordansInequality.epsf}\end{center}\end{figure}

For $0\leq x\leq \pi/2,$

\begin{displaymath}
{2\over\pi}x \leq\sin x\leq x.
\end{displaymath}


References

Yuefeng, F. ``Jordan's Inequality.'' Math. Mag. 69, 126, 1996.




© 1996-9 Eric W. Weisstein
1999-05-25