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Perfect Proportion

Since

\begin{displaymath}
{2a\over a+b}={2ab\over (a+b)b},
\end{displaymath} (1)

it follows that
\begin{displaymath}
{a\over {a+b\over 2}} = {{2ab\over a+b}\over b},
\end{displaymath} (2)

so
\begin{displaymath}
{a\over A} = {H\over b},
\end{displaymath} (3)

where $A$ and $H$ are the Arithmetic Mean and Harmonic Mean of $a$ and $b$. This relationship was purportedly discovered by Pythagoras.

See also Arithmetic Mean, Harmonic Mean




© 1996-9 Eric W. Weisstein
1999-05-26