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Conic Section Tangent

Given a Conic Section

\begin{displaymath}
x^2+y^2+2gx+2fy+c=0,
\end{displaymath}

the tangent at $(x_1,y_1)$ is given by the equation

\begin{displaymath}
xx_1+yy_1+g(x+x_1)+f(y+y_1)+c=0.
\end{displaymath}




© 1996-9 Eric W. Weisstein
1999-05-26