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Curvature Vector


\begin{displaymath}
{\bf K}\equiv {d{\bf T}\over ds},
\end{displaymath}

where ${\bf T}$ is the Tangent Vector defined by

\begin{displaymath}
{\bf T}\equiv {{d{\bf x}\over ds}\over \left\vert{d{\bf x}\over ds}\right\vert}.
\end{displaymath}




© 1996-9 Eric W. Weisstein
1999-05-25