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Extended Mean-Value Theorem

Let the functions $f$ and $g$ be Differentiable on the Open Interval $(a,b)$ and Continuous on the Closed Interval $[a,b]$. If $g'(x) \not = 0$ for any $x \in (a,b)$, then there is at least one point $c \in(a,b)$ such that

\begin{displaymath}
{f'(c)\over g'(c)} = {f(b)-f(a)\over g(b)-g(a)}.
\end{displaymath}

See also Mean-Value Theorem




© 1996-9 Eric W. Weisstein
1999-05-25