An Apodization Function
|
(1) |
having Instrument Function
The peak (in units of ) is 2. The extrema are given by letting
and solving
|
(3) |
|
(4) |
|
(5) |
Solving this numerically gives ,
,
, ...for the first few solutions. The
second of these is the peak Positive sidelobe, and the third is the peak Negative sidelobe. As a fraction of the peak,
they are 0.128375 and . The Full Width at Half Maximum is found by setting
|
(6) |
and solving for , yielding
|
(7) |
Therefore, with ,
|
(8) |
See also Apodization Function
© 1996-9 Eric W. Weisstein
1999-05-26