## Uniform Apodization Function

 (1)

having Instrument Function
 (2)

The peak (in units of ) is 2. The extrema are given by letting and solving
 (3)

 (4)

 (5)

Solving this numerically gives , , , ...for the first few solutions. The second of these is the peak Positive sidelobe, and the third is the peak Negative sidelobe. As a fraction of the peak, they are 0.128375 and . The Full Width at Half Maximum is found by setting
 (6)

and solving for , yielding
 (7)

Therefore, with ,
 (8)